Question

solve this...... .....

Answer 1

you can see your answer

Answer 2

$Given, \\ \\ (\tan\theta + \cot\theta)^{2} \\ \\ = \tan^{2}\theta + \cot^{2}\theta + 2\tan\theta . \cot\theta \\ \\ = \sec^{2}\theta - 1 + cosec^{2}\theta -1 + 2\tan\theta . \frac{1}{\tan\theta} \\ \\ = \sec^{2}\theta + cosec^{2}\theta \\ \\ Proved. \\ \\ Again \\ \\ \sec^{2}\theta + cosec^{2}\theta \\ \\ = \frac{1}{cos^{2}\theta} + \frac{1}{sin^{2}\theta} \\ \\ = \frac{sin^{2} + cos^{2}\theta}{sin^{2}\theta.cos^{2}\theta} \\ \\ = \frac{1}{sin^{2}\theta.cos^{2}\theta} \\ \\ = sec^{2}\theta .cosec^{2}\theta \\ \\ \textbf{Hence Proved}$