solve this 7 question : p²x²+(p²-q²)x-q²=0 by quadratic formula only
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x= (-b+-√b^2-4ac)/2a
= (q^2-p^2+-√p^4+q^4-2p^2×q^2+4p^2×q^2)/. 2p^2
=(q^2-p^2+-√p^4+q^4+2p^2×q^2)/2p^2
=(q^2-p^2+-√(p^2+q^2)^2)/2p^2
=(q^2-p^2+-p^2+q^2)/2p^2
=(q^2-p^2+p^2+q^2)/2p^2 or (q^2-p^2-p^2-q^2)/2p^2
=2q^2/2p^2 or -2p^2/2p^2
=q^2/p^2 or -1
= (q^2-p^2+-√p^4+q^4-2p^2×q^2+4p^2×q^2)/. 2p^2
=(q^2-p^2+-√p^4+q^4+2p^2×q^2)/2p^2
=(q^2-p^2+-√(p^2+q^2)^2)/2p^2
=(q^2-p^2+-p^2+q^2)/2p^2
=(q^2-p^2+p^2+q^2)/2p^2 or (q^2-p^2-p^2-q^2)/2p^2
=2q^2/2p^2 or -2p^2/2p^2
=q^2/p^2 or -1
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