solve..this........
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Step-by-step explanation:
Given:-
PQRS and ABRS are parallelograms.
To prove:-
i) ar(PQRS)=ar(ABRS)
ii) ar (AXS)= 1/2 ar(PQRS)
Proof:-
PQ║RS
∵PQ extended to B, PB║RS
∴║gms lying between same base(RS) and same parallel(PB║RS)ARE equal in area.
∴ar(PQRS)=ar(ABRS)
If a triangle and a ║qm are on the same base and between the same parallels then area of triangle is half times area of ║gm.
In ΔAXS and ║gm ABRS.
Same base⇒AS
Same parallel⇒AS║BR
∴ar(AXS)= 1/2 ar(ABRS)
∵ from i)
∴ar(AXS)= 1/2 ar(PQRS) because ar(PQRS) =ar(ABRS)
MARK AS BRAINLIEST....
amitkr45:
lot of thanks bro
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