Math, asked by amitkumar44481, 1 year ago

solve this..............​

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Answered by Khushi99445
2

Here is your answer user.

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Answered by Anonymous
36

SOLUTION:-

 \implies \sf \bigg( \frac{256}{625}  \bigg) {}^{ \frac{ - 3}{4} }  \times  \bigg( \frac{81}{16}  \bigg)  {}^{ \frac{ - 3}{2} }  \div   \bigg(\frac{9}{2}  \bigg) {}^{ - 3}  \\  \\

 \implies \sf   \frac{{(256)} {}^{ \frac{ - 3}{ \: 4} }} {(625) {}^{ \frac{ - 3}{ \: 4} }  } \times  \frac{(81) {}^{ \frac{ - 3}{ \: 2} } }{{(16)} {}^{ \frac{ - 3}{2} }}   \div  \frac{(9) {}^{ - 3} }{(2 ){}^{ - 3} }  \\  \\

 \implies \sf  \frac{(14) {}^{2 \times  \frac{ -  3}{ \: 4} } }{(25) {}^{2 \times  \frac{ - 3}{ \: 4} } } \times  \frac{(9) {}^{2 \times  \frac{ - 3}{ \: 2} } }{(4) {}^{2 \times  \frac{ - 3}{ \: 2} } }   \div \frac{(9) {}^{ - 3} }{(2 ){}^{ - 3} }   \\  \\

 \implies \sf \frac{(14) {}^{ \frac{ - 3}{ \: 2} } }{(25) {}^{ \frac{ - 3}{ \: 2} } }   \times  \frac{(9)  {}^{ - 3} }{(2) {}^{ - 3} }  \times  \frac{(2) {}^{ - 3} }{(9) {}^{ - 3} }  \\  \\

 \implies \sf \frac{(14) {}^{ \frac{ - 3}{ \: 2} } }{(25) {}^{ \frac{ - 3}{ \: 2} } }   \times  \frac{ \cancel{(9)  {}^{ - 3} }}{ \cancel{(2) {}^{ - 3} }}  \times  \frac{ \cancel{(2) {}^{ - 3}} }  { \cancel{(9) {}^{ - 3} }  }\\  \\

 \implies \sf \frac{(14) {}^{ \frac{ - 3}{ \: 2} } }{(25) {}^{ \frac{ - 3}{ \: 2} } }  \\

 \implies \sf \bigg( \frac{14}{25}  \bigg) {}^{ \frac{ - 3}{ \: 2} }   \\  \\

Hence,simplified

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