Question

Solve this!!!!!!!!!!!​

Answer 1

total current =0.5A

this is the answer

Answer 2

For 1st bulb

p=50W

V=220V

R=V^2/P

R= 220×220/50

R=4840/5

R= 968ohm

For 2nd bulb

P=60W

V=220V

R=220×220/60

R= 4840/6

R=806.66ohm

if bulbs are connected in parallel

1/R=1/R1+1/R2

1/R=1/968+6/4840

1/R=(4840+5808)/4685120

R=4685120/10648

R=440 ohm

According to ohm's law,

V=IR

I=V/R

I=220/440

I=1/2

I=0.5 ampere

So, 0.5 ampere current will flow through main conductor .

:) hope it helps you