Question

solve this 8x^2+76x+68=0 find roots..​

Answer 1

Answer:

1, 68/8

Step-by-step explanation:

8x^2+76x+68

8x^2 +8x+68x+68

8x(X+1)+68(X+1)

(X+1)(8x+68)

X=1,X=68/8

Answer 2

Answer:

p(x)=8x²+76x+68

•Using Discriminant formula,

d=b²-4ac

a=8

b=76

c=68

→(76)²-4×8×68

d=5776-2176

√d=±√3600

√d=±60

taking x(+)=$\frac{-b+ \sqrt{d}}{2a}$

=$\frac{-(-76)+60}{2×8}$

x=$\frac{135}{16}$

taking x(-)=$\frac{-b- \sqrt{d}}{2a}$

=$\frac{-(-76)-60}{2×8}$

x=$\frac{16}{16}$

x=1

$\rule{200}{1}$