Question

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Answer 1

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Answer 2

Please find below the solution to the asked query : 

We have,Internal radius, r = 15 cmExternal radius, R = 16 cm(1).Area of bowl to be painted = 2πr2+2πR2=2π[r2+R2]=2π[162+152]=2π[256+225]=962π cm2Cost of painting 1 cm2 of area  = Re 0.35Cost of painting 962π cm2 area = Rs[0.35×962π] = 35100×962×227 = Rs 1058.20(2).Area of bowl to be painted = 2πr2+2πR2+π[R2−r2]=962π + π[162−152]=962π+π×31=993π cm2Cost of painting 1 cm2 of area  = Re 0.35Cost of painting 993π cm2 area = Rs[0.35×993π] = 35100×993×