Question

Solve this,

A concave mirror produces a real image 10 mm tall, of an object 2.5 mm tall placed at 5 cm from the mirror. Calculate focal length of the mirror and the position of the image.


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Answer 1

Answer:

h2 = 1cm = 10mm (real image), h1 = 2.5mm, u = -5cm = -50mm

m = - h2/h1

m = - (10/2.5)

m = -4

and we know that

m = - (v/u)

and we know that

m = - (v/u)

-4 = - (v/(-50)

V = - 200 mm

V = - 20 cm

The image is formed 20 cm in front of the mirror.

And,

1/v + 1/u = 1/f

1/-20 + 1/-5 = 1/f

1/f = -25/100

f = - 4 cm