Solve this....
A laser light beam of power 20 mW is focused
on a target by a lens of focal length 0.05 m. If the aperture of
the laser be 1 mm and the wavelength of its light 7000 Å
calculate the angular spread of the laser, the area of the target
hit by it, and the intensity of the impact on the target......NO SPAMS.....WRONG ANS WILL BE REPORTEDDD!!!!!
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Explanation:
Given A laser light beam of power 20 m W is focused on a target by a lens of focal length 0.05 m. If the aperture of the laser be 1 mm and the wavelength of its light 7000 Å calculate the angular spread of the laser, the area of the target hit by it, and the intensity of the impact on the target.
- Given P = 20 mW = 20 x 10^-3 W
- Focal length f = 0.05 m, d = 1 mm = 1 x 10^-3 m, λ = 7000 A = 7000 x 10^-10 m, theta = 7 x 10^-4 radians
- Linear speed of the laser s = f x theta
- = 0.05 x 7 x 10^-4
- = 0.35 x 10^-4 m
- Now area of target hit by laser = s^2
- = (0.35 x 10^-4)^2
- = 0.1225 x 10^-8
- = 1.225 x 10^-9 sq m
- So intensity of impact on the target = power of the laser beam / area hit by the laser beam.
- = 20 x 10^-3 / 1.225 x 10^-9 W / m^2
- = 16.326 x 10^6 W/m^2
- = 1.632 x 10^7 W / m^2
Reference link will be
https://brainly.in/question/12362325
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