solve this: a(xdy+2ydx)=xydy
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Given a(xdxdy+2y)=xydxdy</p><p>or y(a−y)dy=x2adx</p><p>or yady+x2adx=dy</p><p>Integrating,weget</p><p>∫yady+∫x2adx=∫dy</p><p> alogy+2alogx=y+c</p><p>or logyx2=ay+c;</p><p>∴yx2=e(y+c)/a=key/a</p><p></p><p></p><p>
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