Question

solve this a²-4a+3 ➗ a²-a-6​

Answer 1

Answer:

If any quadratic equation ax

2

+bx+c has

more then two solutions, it becomes

an identity and has a = b = c = 0

⇒a

2

+4a+3=0⇒a

2

+3a+a+3=0⇒a(a+3)+(a+3)=0

⇒(a+3)(a+1)=0⇒a=−1,−3

And a

2

−a−2=0⇒a

2

−2a+a−2⇒a(a−2)+(a−2)=0

⇒(a+1)(a−2)=0⇒a=−1,2

and a(a+1)=0⇒a=0,−1

only common solution is a=−1

Answer 2

Answer:

a2-4a+3 by a2-a-6

Step-by-step explanation:

q(x) =1

r(x) =-3a+9