SOLVE THIS ABOVE QUESTION
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f(x)=x^2+px-4=0
f(-4)=(-4)^2+p×(-4)-4=0
;16-4p-4=0
;-4p+12=0
;-4p=-12
;p=3
again. put
x=-4
and p=3
x^2+px+q=0
(-4)^2+3×(-4)+q=0
16-12+q=0
q+4=0
q=-4
p=3,;and q=-4
is your answer
f(-4)=(-4)^2+p×(-4)-4=0
;16-4p-4=0
;-4p+12=0
;-4p=-12
;p=3
again. put
x=-4
and p=3
x^2+px+q=0
(-4)^2+3×(-4)+q=0
16-12+q=0
q+4=0
q=-4
p=3,;and q=-4
is your answer
ishu538:
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u r r9
am wrong
sorry
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plz mark
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must wlc dear
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