solve this activity with explanation for brainlist
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Answer:
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Lets call height at 4m=A
3m=B
2m=C
1m=D
Potenial energy a A = mgh=(20 x 10 x 4 )J=800 J
Kinetic energy at A =(1/2)mv2
as we know body is stationary at A so v=0 so K.E.=0
Potential energy at B =mgh=(20 x 10 x 3)J =600J
For Kinetic energy at B
By equation off motion- v2- u2=2as
=>v2-0=2(10)(1)
=>v2=20
Kinetic energy at B=(1/2)mv2
=(1/2)(20)(20) J .......[v2=20 as proven above]
=200J
Potential energy at C =mgh=(20 x 10 x 2)J
=400J
For Kinetic energy at C
by using equation of motion-v2-u2=2as
=>v2-0=2 x 10 x 2
=>v2=40
Kinetic energy at C =(1/2)mv2
=(1/2)(20)(40) J .....[v2 = 40 as proven above]
=400J
Potential energy at D =mgh=(20 x 10 x 1)J
=200J
For Kinetic energy at D
By using equation of motion- v2 - u2=2as
=>v2 - 0=2 x 10 x 3
=>v2=60
Kinetic energy at D =(1/2)mv2
=(1/2)(20)(60) J
=600 J
hope it helps ......:)
Explanation:
Given that,
the mass of body = 20 kg
It is dropped from 4 m
when the height is 4 m from ground
portential energy = mgh
= 20 × 10 × 4
= 800 J
it velocity will zero
so,
Kinetic energy = 0
Now,
when the height = 3 m
so,
pottential energy = 20 × 10 × 3
= 600 J
it has travelled 1 m
so,
V = √2gh
= √2 × 10 × 1
= 2√5
Velocity = 2√5 m/s
so,
kinetic energy = ½ × 20 × 2√5²
= 200 j
Now,
Height = 2 m
so,
Pottential energy = 20 × 10 × 2
= 400 j
Now,
velocity = √2 × 10 × 2
= 2√10 m/s
so,
Kinetic energy = ½ × 20 × 2√10²
= 400 j
Now,
Height = 1 m
so,
Pottential energy = 20 × 10 × 1
= 200 j
distance travelled by it = 3m
Now,
velocity = √2 × 10 × 3
= 2√15
so,
Kinetic energy = ½ × 20 × 2√15²
= 600 J
________________
Height = 4 m
Kinetic energy = 0 J
Pottential energy = 800 J
_____________________
Height = 3 m
kinetic energy = 200 J
Pottential energy = 600 J
_____________________
Height = 2 m
kinetic energy = 400 J
Potential energy = 400 J
_____________________
Height = 1 m
kinetic energy = 600 J
Pottential energy = 200 J