Math, asked by priya14356, 3 months ago

solve this algebra please ​

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Answered by Anonymous
3

Step-by-step explanation:

 \frac{3i \times (2 - 10i)}{(2 + 10i) \times (2 - 10i)}

 \frac{6i -  {30i}^{2} }{4 -  {100i}^{2} }

 \frac{6i - 30 - (1)}{4 - 100 - (1)}

 \frac{6i + 30  }{4  + 100}

 \frac{2(3i + 15)}{104}

 \frac{3i + 15}{52}

 \frac{15}{32 +  \frac{3}{15}i }

 \frac{15}{52}  +  \frac{3}{52}i

Answered by roshani943
2

Answer:

The above answer is correct

Mark the above answer as BRAINLIEST

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