Question

solve this alsoo plzz​

Answer 1

Answer:

ans : p = 2

Step-by-step explanation:

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and explanation

Answer 2

Answer:

p = 2

$as \: we \: know \: \\ \\ \ sum \: of \: zeros \: = \alpha + \beta = \frac{ - b}{ \: a} \\\ \alpha + \beta = \frac{ -( - 7)}{p} \\ \\ \alpha + \beta = \frac{7}{p} - - - - - (1) \\ \\ but \: \alpha = \frac{4}{3} \beta \\ \\ by \: putting \: value \: of \: \alpha \: in \: equation \: 1 \\ \\\ \frac{4}{3} \beta + \beta = \frac{7}{p} \\ \\ \frac{4 \beta + 3 \beta }{3} = \frac{7}{p} \\ \\ \frac{7 \beta }{3} = \frac{7}{p} \\ 7 \: iso \: both \: sides \: so \: it \: will \: cancel \: \: out \: so \: by \: bcm\\ \beta = \frac{3}{p} \\ \\ nowas \: we \: know \: product \: of \: zeros \: = \alpha \beta = \frac{c}{a}$

$so \: \alpha \beta = \frac{6}{p} \\ as \: we \: know \: \beta = \frac{3}{p} \\ \alpha \frac{3}{p} = \frac{6}{p \: } \\ \\ \alpha = 2 \: \: \ \\ \\ now \: \alpha + b = \frac{ - b}{a} \\ \\ \alpha + \beta = \frac{7}{p} \\ but \: \alpha = 2 \: and \: \beta = \frac{3}{p} \\ \\ \\ so \: 2 + \frac{3}{p} = \frac{7}{p} \\ \\ 2 = \frac{7}{p} - \frac{3}{p} \\ \\ 2 = \frac{7 - 3}{p} \\ \\ 2 = \frac{4}{p} \\ \\ 2p \: = 4 \\ \\ so \: p = 2 \\ \\ \\ \\ therefore \: value \: ofp \: = 2$

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