solve this and explain

Answers
Answer:
Option D
Explanation:
Let the third spherical conductor be A
Initial force=F=kq^2/r^2
When you touch A with B, total charge present on B and A gets equally divided.
Total charge on both B and A =q+0=q
So after touching, charge on both
B and A=q/2
Now A is touched with C
Total charge on both A and C=q/2+q=3q/2
Now this total charge gets equally divided between A and C.
So after touching, charge on both
A and C=3q/4
Now charge on B =q/2
charge on C=3q/4
Force=3Kq^2/8r^2=3F/8
hyy mate ✌️
Let B and C have charge Q each initially and are separated by r distance.
Coulomb force between them, F = KQ^2/ r^2 ...............(1)
Now an identical uncharged spherical conductor A is brought in contact with B. They will share equal charge among themselves.
Charge on A = Q/2
Charge on B = Q/2
Now the conductor A is brought in contact with C. They will share equal charge among themselves.
Therefore, Charge on A or C = Q+Q/2/2 = 3Q/4
New Culomb force between B and C :
F^1 = K Q/2 * 3Q/4 / r^2 = 3 KQ^2/ 8 r^2
From first we get: F^1 = 3/8 F
For reference see the attachment.....xd!!!!
hope it will help you ❣️❣️
