Question

Solve this.........................
And I marked..

Answer 1

First, from the graph, we need to find the acceleration of the lift in the upward direction.

Let the acceleration be a.

It is the slop of the graph v-t

$Slope = \frac{20-0}{2-0}$

Slope = a = 10 m/s^2

Now, the weight of the body while going up = m (g + a)

Weight = M (10 + 10)

Weight = 20M Newtons.

Hence, the weight of the person at 1 seconds is 20M Newtons.

Answer 2

First, from the graph, we need to find the acceleration of the lift in the upward direction.

Let the acceleration be a.

It is the slop of the graph v-t

Slope = \frac{20-0}{2-0}Slope=2−020−0​

Slope = a = 10 m/s^2

Now, the weight of the body while going up = m (g + a)

Weight = M (10 + 10)

Weight = 20M Newtons.

Hence, the weight of the person at 1 seconds is 20M Newtons.

MARK BRAINLIEST