solve this and send the answer . who will solve this he or she will get 15 points
Attachments:
![](https://hi-static.z-dn.net/files/d16/20d157f0e1a7d6e936023e42f3942a79.jpg)
Answers
Answered by
1
Answer:
15Q:
A coin is tossed twice if the coin shows head it is tossed again but if it shows a tail then a die is tossed. If 8 possible outcomes are equally likely. Find the probability that the die shows a number greater than 4, if it is known that the first throw of the coin results in a tail
A) 1/3
B) 2/3
C) 2/5
D) 4/15
Answer: A) 1/3
Explanation:
Here Sample space S = { HH, HT, T1, T2, T3, T4, T5, T6 }
Let A be the event that the die shows a number greater than 4 and B be the event that the first throw of the coin results in a tail then,
A = { T5, T6 }
B = { T1, T2, T3, T4, T5, T6 }
Therefore, Required probability = P(AB)=P(A∩B)P(B)=28/68/=13
Similar questions