English, asked by navyasingh14245, 7 months ago

solve this and send the answer . who will solve this he or she will get 15 points​

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Answered by sudiptamaji2007
1

Answer:

15Q:

A coin is tossed twice if the coin shows head it is tossed again but if it shows a tail then a die is tossed. If 8 possible outcomes are equally likely. Find the probability that the die shows a number greater than 4, if it is known that the first throw of the coin results in a tail

A) 1/3

B) 2/3

C) 2/5

D) 4/15

Answer: A) 1/3

Explanation:

Here Sample space S = { HH, HT, T1, T2, T3, T4, T5, T6 }

Let A be the event that the die shows a number greater than 4 and B be the event that the first throw of the coin results in a tail then,

A = { T5, T6 }

B = { T1, T2, T3, T4, T5, T6 }

Therefore, Required probability = P(AB)=P(A∩B)P(B)=28/68/=13

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