Question

solve this ans plz. ​

Answer 1

Q]____?

=> a) 560 J

Explanation :

For path AB applying first law of thermodynamics.

dQ = dU + dW or dQ = Uʙ - Uᴀ + dW

or 600 = Uʙ - Uᴀ + 0

...[ for isochoric process dV = 0 so,dW =0]

Uʙ - Uᴀ = 600 _[i]

For path BC,

dQ = dU + dW

200 = Uᴄ - Uʙ + pʙ ( Vᴄ - Vʙ )

...[ as BC is isolated process ]

200 = Uc - Uʙ + 8 × 10^4 (5× 10^- 3 - 2× 10^-3 )

or 200 = Uᴄ - Uʙ + 240

Uᴄ - Uʙ = -40 J _[ii]

For AC, change in internal energy can be calculated by adding Eqs. [i] and [ii],

= Uᴄ - Uᴀ = Uᴄ - Uʙ + Uʙ - Uᴀ

= -40 + 600 = 560 J

Thus,

The change in the internal energy of the system in process AC would be 560 J !

Answer 2

Explanation:

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