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Answer: 12k-11k=6 k=6
Step-by-step explanation:
PQ || BC In ΔABC=ΔAPQ So ∠1=∠2 ( corresponding angles) ∠3= ∠4 ( corresponding angles) ∠A is common so ΔABC ~ ΔAPQ So AP/AB= AQ/AC
k / ( k+2k+2) =(k+3) / (k+3+2k+9)
k/(3k+2) = (k+3)/(3k+12)
k*(3k+12)=(3k+2)(k+3)
3k²+12k=3k²+9k+2k+6
12k - 11k=6
k = 6
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Answer:
k = 6
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ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘꜱ ʏᴏᴜ. ☺❤
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