Question

solve this ASAP!!!!!!!!!!!!!​

Answer 1

Hi buddy

Here is your answer

Hope it help you

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#sibi ❤️

Answer 2

Step-by-step explanation:

Given,

∠ABC = 66°, ∠DAC = 38°, CE is ⊥ to AB and AD ⊥ BC.

(i)

From ΔBCE,

Sum of angles = 180°.

⇒ 66° + 90° + ∠BCE = 180°

⇒ 156° + ∠BCE = 180°

⇒ ∠BCE = 180 - 156

⇒ ∠BCE = 24°

(ii)

From ΔACD,

⇒ 38° + 90° + ∠ACD = 180°

⇒ 128° + ∠ACD = 180°

⇒ ∠ACD = 52°

Thus,

∠ACP = ∠ACD - ∠BCE

         = 52° - 24°

         = 28°

Now,

In ΔAPC,

∠PAC(38°) > ∠PCA(28°)

[∵ Side opposite to greater angle is greater]

Therefore,

∴ PC > AP

Hope it helps!