Question

solve this Asap !!!!!!!!!​

Answer 1

Answer:

Answer:

\begin{gathered}\sf GivEn \begin{cases} & \sf{Initial\; Velocity, u = \bf{0\;m/s}} \\ & \sf{Distance, d = \bf{400\;m} } \\ & \sf{Time, t = \bf{10\;s}} \\ & \sf{Mass, m = 5\;metric\;tonne = \bf{5000\; kg}}\end{cases}\end{gathered}

GivEn

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InitialVelocity,u=0m/s

Distance,d=400m

Time,t=10s

Mass,m=5metrictonne=5000kg

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☯ By using 2nd equation of motion, \begin{gathered}\\ \\\end{gathered}

\begin{gathered}\star\;{\boxed{\sf{\purple{s = ut + \dfrac{1}{2} at^2}}}}\\ \\\end{gathered}

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s=ut+

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at

2

\begin{gathered}:\implies\sf 400 = 0 \times 10 + \dfrac{1}{2} a(10)^2\\ \\\end{gathered}

:⟹400=0×10+

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a(10)

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\begin{gathered}:\implies\sf 400 = 0 + \dfrac{1}{2} \times 100a\\ \\\end{gathered}

:⟹400=0+

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×100a

\begin{gathered}:\implies\sf 400 = \dfrac{1}{ \cancel{2}} \times \cancel{100}a\\ \\\end{gathered}

:⟹400=

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1

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100

a

\begin{gathered}:\implies\sf 400 = 50a\\ \\\end{gathered}

:⟹400=50a

\begin{gathered}:\implies\sf a = \cancel{ \dfrac{400}{50}}\\ \\\end{gathered}

:⟹a=

50

400

\begin{gathered}:\implies{\boxed{\frak{\pink{a = 8\;m/s^2}}}}\;\bigstar\\ \\\end{gathered}

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a=8m/s

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☯ Now, As we know, \begin{gathered}\\ \\\end{gathered}

\begin{gathered}\star\;{\boxed{\sf{\purple{F = ma}}}}\\ \\\end{gathered}

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F=ma

\begin{gathered}:\implies\sf F = 5000 \times 8\\ \\\end{gathered}

:⟹F=5000×8

\begin{gathered}:\implies{\boxed{\frak{\pink{F = 40,000\;N}}}}\;\bigstar\\ \\\end{gathered}

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F=40,000N

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\therefore\;{\underline{\sf{Hence,\;Force\;acting\;on\;body\;is\;40,000\;N.}}}∴

Hence,Forceactingonbodyis40,000N.