Question

solve this by 3 equation of motion
2as = v^2 -u^2
pleaseeeeeeeeeeeeeeeeee

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Answer 1

Answer:

HIIII

Explanation:

Given,

initial velocity(u) = 0m/s

 final velocity(v) = 50m/s

 acceleration(a) = -10ms^-2

        distance(s) = ?

Given equation =

                  $2as = v^{2} - u^{2}$

          2×-10× s = 0^2 - 50^2

            -20 × s = 0 - 2500

                     s = -2500/-20

                     s = 125

Therefore, distance = 125

     

Answer 2

Answer:

Final velocity (v) squared equals initial velocity (u) squared plus two times acceleration (a) times displacement (s). v2=u2+2as. Solving for v, final velocity (v) equals the square root of initial velocity (u) squared plus two times acceleration (a) times displacement (s).