Question

Solve this by completing square method plzz today is my exam!!!

Answer 1

${x}^{2} + x - 20 = 0 \\ \\ {x}^{2} + 5x - 4x - 20 = 0 \\ \\ x(x + 5) - 4(x + 5) = 0 \\ \\ (x + 5)(x - 4) = 0 \\ \\ hence, \: value \: of \: x \: is \: either \: 4 \: or \: (- 5)$

Answer 2

Hope it helps u ^_^ ^_^ ^_^

plzz mark it as brainliest

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