Question

Solve this by elimination method: 3x+4y=12, 6x+8y=20

Answer 1

ANSWER:

• There is no value of x and y satisfy the both equation.

GIVEN:

• 3x+4y = 12
• 6x+8y = 20

TO FIND:

• Value of 'x'and 'y'.

SOLUTION:

=> 3x+4y = 12 .....(i)

Muntiplying both sides by 2

=> 2(3x+4y) = 12×2

=> 6x+8y = 24.

=> 6x+8y = 20

Muntiplying both sides by 1.

=> 6x+8y = 20 .....(ii)

Subtracting eq (I) from (ii)

=> (6x+8y)-(6x+8y) = 20-24

=> 0 ≠ -4

There is no value of x and y satisfy the both equation.

NOTE:

• This method of finding the value of 'x'and 'y' is called elimination method.

Answer 2

IT MAY HELP YOU IN SOLVING THIS SUM OF CHAPTER 3