solve this by elimination method
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Given Equation is 2x + 5y = (8/3) --------- (1)
Given Equation is 3x - 2y = (5/6) --------- (2)
On solving (1) * 3 & (2) * 2 , we get
= > 6x + 15y = 8
= > 6x - 4y = 5/3
--------------------
19y = 8 - (5/3)
19y = 19/3
y = 1/3.
Substitute y = (1/3) in (1), we get
= > 2x + 5y = (8/3)
= > 2x + 5(1/3) = (8/3)
= > 2x + 5/3 = 8/3
= > 2x = 8/3 - 5/3
= > 2x = 3/3
= > 2x = 1
= > x = 1/2.
Therefore the value of x = 1/2 and y = 1/3.
Hope this helps!
siddhartharao77:
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Answered by
6
2x+5y = 8/3 ........1
3x-2y=5/6 .............2
now, multiply by 2 in equation 1st , we get -
4x+10y=16/3 ............3
and now multiply by 5 in equation 2nd we get -
15x-10y=25/6 ..............4
Now , add equation 3 and 4, we get -
x =1/2
So put this value of x in equation 3 , we get -
y= 1/3
so the value of x is 1/2 and the value of y is 1/3
3x-2y=5/6 .............2
now, multiply by 2 in equation 1st , we get -
4x+10y=16/3 ............3
and now multiply by 5 in equation 2nd we get -
15x-10y=25/6 ..............4
Now , add equation 3 and 4, we get -
x =1/2
So put this value of x in equation 3 , we get -
y= 1/3
so the value of x is 1/2 and the value of y is 1/3
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