Question

solve this by elimination method thank you ​

Answer 1

Answer:

x = 0

y = 0

Step-by-step explanation:

$\sqrt{2}x+\sqrt{3}y=0 ~~~~~~~~~~~~ * \sqrt{3} \\\\\sqrt{3}x-\sqrt{8}y=0~~~~~~~~~~~~*\sqrt{2}\\\\============================================\\\\\sqrt{6}x+3y=0\\\sqrt{6}x-4y=0\\\\on~subtracting~we~get:\\\\7y=0\\y=0\\\\On~subs~y=0~in first equation~we~get:\\\\\sqrt{2}x+0=0\\\\\therefore~x=0$

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Answer 2

√2x + √3y = 0 ....(1)

√3x + √8y = 0 ....(2)

multiply equation (1) by √3 and equation (2) by √2

√6x + 3y = 0 ....(3)

√6x + 4y = 0 ....(4)

subtracting equation (3) and (4)

0 +1y = 0

y = 0

put y = 0 in equation (1)

√2x + √3y = 0

√2x + 0 = 0

x = 0

solution is (0, 0)

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