solve this by l hospital rule
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Answer:e^-1/6
Step-by-step explanation:
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Attachments:
Answered by
0
Answer:
Step-by-step explanation:
i will tell you short cut
if you get lim x tends a numerator =1
then apply this formula
e^lim x tends a denominator (numerator -1)
e^lim x tends 0 (1/x^2)(sinx/x-1)
apply l hospitals rule
you get
e^lim x tends 0 (-(cos x)/6)
e^-1/6
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