Chemistry, asked by prakhar04, 11 months ago

solve this by log method

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Answered by Anonymous

[OH-] = 10^-4

pOH = - log [OH -]

pOH = - log ( 10^-4)

pOH = 4

⚫pOH + pH = 14

4 + pH = 14

pH = 14 - 4

$\fbox{pH\: = \:10}$

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Anonymous: Wait....

prakhar04: i am getting confused : ( nd wasting my time on this silly question

Anonymous: log m^n = n log m

Anonymous: So, - ( - 4) × log (10) [ log 10 =1 ]

Anonymous: so, 4

Anonymous: Actually, it is 4 × log 10 = 4 ( multiplication)

prakhar04: oooooo

prakhar04: thank u very very much

prakhar04: ; )

Anonymous: Welcome.

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