solve this by quadratic equations
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Since (x-a)² is the only term that contains the term a in the numerator and
(x-b)² is the only term that contains the term b in the numerator
we equate LHS to RHS
(x-a)² = a² (x-b)² = b²
x-a = ±a x-b = ±b
x = 2a or 0 x = 2b or 0
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