Solve this by substitution method :-

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Solution :
The equations are :
(a) 2y = [ 30 ]/[ x - 1]
(b) y = [ 30 ]/[ 2 + x ] .
Here , from the second equation, we can get the value of y as ( 30 ) / ( x + 2 ) .
Substituting that value in the first equation , we get :
2 × [ 30 / x + 2 ] = [ 30 / x - 1 ] .
Cancelling the common terms , we get :
2 ( x - 1 ) = ( x + 2 )
=> 2x - 2 = x + 2
=> x = 4 .
y = 30 / ( x + 2 )
=> y = 30 / 6
=> y = 5 .
Hence , for the value of x and y to be 4 and 5 respectively , the equation satisfies .
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