Math, asked by samumahajan011, 8 months ago

Solve this by substitution method (x+1)/2+(y-1)/3=9 ; (x-1)/3+(y+1)/2=8

Answers

Answered by sanskarbansalbtp
2

Answer:

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Step-by-step explanation:

Attachments:
Answered by MissionRanaMagar
2

Answer:

x=3 and y=7

Step-by-step explanation:

Solution;

Given;

(x+1)/2+(y-1)/3=9

or, {3(x+1)+2(y-1)}/6=9

or, (3x+3+2y-2)/6=9

or, 3x+1+2y=9x6

or, 3x = 54-1-2y

or, x = (53-2y)/3........(i)

(x-1)/3+(y+1)/2=8

or, {2(x-1)+3(y+1)}/6=8

or, (2x-2+3y+3)/6=8

or, 2x+3y+1=8x6

or, 2x(53-2y)/3 + 3y =48-1

or, (106-4y+9y)/3=47

or, 5y+106 = 47x3

or, 5y = 141 - 106

or y = 35/5

or, y=7

Substituting y=7 in (i)

x=(53-2y)/3

=(53-2x7)/3

=(53-14)/3

=39/3

=13

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