Question

Solve this by trial and error method-

4m+(2/5)=1

Answer 1

Answer:

4m +2/5 = 1

4m = 1 − 2/5

= 5−2 /5 = 3/5

m= 3/5×4

answer = 3/20

Answer 2

Answer:

The value of m is $\frac{3}{20}$.

Step-by-step explanation:

Given equation is $4m+\frac{2}{5}=1$.

We need to find the value of m by using trial and error method.

Substitute the value of $m$ as $0$.

$4(0)+\frac{2}{5}=1$

$\frac{2}{5} \neq 1$.

Substitute the value $m=1$.

$4(1)+\frac{2}{5}=1$

$\frac{22}{5}\neq 1$.

Let us take a value between 0 and 1.

Now substitute the value $m=\frac{1}{4}$

$4(\frac{1}{4} )+\frac{2}{5}=1$

$\frac{7}{5}\neq 1$.

Let us take a value between 0 and $\frac{1}{4}$

Now substitute the value $m=\frac{1}{10}$

$4(\frac{1}{10})+\frac{2}{5}=1$

$\frac{4}{5}\neq 1$

Take a value between $\frac{1}{10}$ and $\frac{1}{4}$.

We know $\frac{1}{10}=\frac{2}{20}$, $\frac{1}{4}=\frac{5}{20}$

Now take the value $m=\frac{3}{20}$

$4(\frac{3}{20})+\frac{2}{5}=1$

$\frac{3}{5}+\frac{2}{5}=1$

$1=1$.

So the value of $m$ is $\frac{3}{20}$.