Question

solve this
by using one opposite sides of parallelogram find p

jo karega mai usko follow karunga​

Answer 1

We know that opposite sides of a parallelogram are equal. So we need to use distance formula and solve it.

AB and CD are opposite sides.

So AB = CD

i.e.,

$\sqrt{(8-6)^2+(2-1)^2} = \sqrt{(9-p)^2+(4-3)^2}$

${(8-6)^2+(2-1)^2} = {(9-p)^2+(4-3)^2}$

$4+1 = (9-p)^2 + 1$

$4 = (9-p)^2$

$9-p = +2$   OR   $9-p = -2$

p = 7   OR   p = 11.

Now find AD and BC using both of the above values to check which one is right.

$BC = \sqrt{(9-8)^2 + (4-2)^2}$

$BC = \sqrt{5}$

Find AD using p = 7

$AD = \sqrt{(7-6)^2+(3-1)^2}$

$AD = \sqrt{5}$

Find AD using p = 11

$AD = \sqrt{(11-6)^2+(3-1)^2}$

$AD = \sqrt{29}$

Since AD and BC are opposite sides of the parallelogram, AD = BC

But only p = 7 satisfies this condition. Hence p = 7 is the correct answer

Answer 2

Answer:

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