Solve this case study question of class 10 from ch- probability
Answers
Given : One Half of the seeds produce White flower. One third produce Yellow flowers and remaining Red flowers
To Find : Probabilities
Red Flower
not Yellow Flower
2 Seeds selected Both produce Yellow
2 Seeds selected Both produce Blue
2 Seeds selected produce one White and one Yellow flower
Solution:
Let say Total Flowers are 6F
White = (1/2)6F = 3F
Yellow = (1/3)6F = 2F
Red = 6F - 3F - 2F = F
Probability Red Flower = F/6F = 1/6
Probability not Yellow Flower = (6F - 2F)/6F = 4/6 = 2/3
Probability that 2 Seeds selected Both produce Yellow = (2F/6F) (2F/6F)
= (1/3)(1/3)
= 1/9
Probability that 2 Seeds selected Both produce Blue = (0/6F)(0/6F) = 0
( as no seed produce blue flower)
Probability that 2 Seeds selected produce White and Yellow flower
= (3F /6F )(2F/6F) + (2F/6F)(3F /6F )
= 1/6 + 1/6
= 1/3
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