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chemistry class XI
Answers
Basic question of thermodynamics
Solution:-
i) C(graphite) +O2=>CO2:∆H°=xKj/mol
ii) C(graphite)+O2/2 =>CO2:∆H°=ykj/mol
iii)CO(g) +O2/2=>CO2 :∆H°=zKJ/mol
On adding equation ii) and iii) i.e z+y ,we get
C(graphite)+CO+(1/2+1/2)O2=>CO+CO2
Cancelling CO from both side ,we get
C(graphite)+O2=>CO2
this is equal to equation reaction of equation i) i.e x
so x=z+y ,is the right answer
From the above theoretical ,we can say that if we will practically intermix the reaction of equation ii) and equation iii) ,then the resultant product that we will get will be the reaction of the equation first.
The algebraic relationships given is (c) x = y + z
From question, the change in enthalpy due to formation of CO₂
Δf° H (CO₂) = x
From question, the change in enthalpy due to formation of CO
Δf° H (CO) = y
The change in enthalpy due to formation of reactant:
ΔrH = Δf° H (CO₂) - Δf° H (CO) - 1/2 Δf° H (O₂)
∵ 1/2 Δf° H (O₂) = 0
Now,
ΔrH = Δf° H (CO₂) - Δf° H (CO) - 0
∴ z = x - y
∴ x = y + z