Question

solve this class 10th question please​

Answer 1

$9 {q}^{2} + 12q + 3 + 1 \\ = 3(3 {q}^{2} + 4q + 1) + 1 \\ = 3m + 1 \: \: \: \: (where \: m = (3 {q}^{2} + 4q + 1) \\ therefore \: the \: square \: of \: any \: positive \: integer \: is \: either \: of \: the \: form \: 3m \: 3m + 1 \\ for \: some \: integer \: m$

Answer 2

Step-by-step explanation:

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