Physics, asked by PRIYANSHU19FEB, 11 months ago

Solve this class 12 question please

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Answered by zahaansajid
0

q = 3 \times  {10}^{ -  6} c \\ r = 2m \\  \\ electric \: field \: intensity =  \frac{kq}{ {r}^{2} }   \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  =  \frac{9 \times  {10}^{9}  \times 3 \times  {10}^{ - 6} }{ {2}^{2} }  =  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: =  \frac{27000}{4}  = 6750

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