Question

Solve this correctly

Answer 1

$\huge {\blue{ \boxed{ \boxed{ \pink{ \underline{ \underline{ \mathfrak{ \red{♡AnSwεr♡}}}}}}}}} \\ let \: y = \sqrt{ {7}^{ \frac{1}{2}} \sqrt{7 {}^{2} \sqrt{ {7}^{ \frac{1}{2}} \sqrt{7 {}^{2} ..........} } }} \\ = > y = \sqrt{ {7}^{ \frac{1}{2}} \sqrt{7 {}^{2} y} } \\ = > {y}^{2} = \sqrt{7} \sqrt[]{49y} \\ = > {y}^{4} = 7 \times 49y \\ = > y {}^{3} = {7}^{3} \\ = > \boxed{y = 7}$

hope it helps you

THANKYOU

Answer 2

Must verify this answer. I tried solving this.. Will be glad if this is correct.♥️

x= 7