Question

solve this correctly otherwaise i 'll report u​

Answer 1

Answer:

If I give the correct one , then also u will reporting me.

Step-by-step explanation:

last question ni a ra to me yahan hi bta ri hu

given hai sin θ =√3/2

→sinθ=sin (π/3)

θ=π/3 =60°

cosec 60°+cot 60°=2/√3 + 1√3=3/√3

=√3

this the ist method,

sinθ=√3/2 =P/H

Pythagoras theorem,

B²=H²-P²

B²= (2)²-(√3)²

B²=4-3

B=1

cosecθ= 1/sinθ

→2/√3

cotθ=B/H

→ 1/√3

therefore, (cosecθ +cotθ)= 2/√3+1/√3= 3/√3

=√3

hence, cosecθ+cotθ=√3

aur e dusra method

I hope ye aapke liye helpful hoga