Physics, asked by shkahlam505, 9 months ago

Solve this derivation K.E=1/2mv2

Answers

Answered by BrainlyConqueror0901
10

\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}

 \red{\underline \bold{To \: Derive:}} \\  \tt:   \implies K.E=  \frac{1}{2}  \: m {v}^{2}

• According to given question :

 \text{Let \: a \:block \: of \: mass \: m \: with \: horizontaly\: applying} \\  \text{force \: F \: and \: travelling \: x \: distance \:attains \: a\: velocity \: v} \\  \\  \bold{As \: we \: know \: that } \\  \tt:  \implies Work \: done = Force \times Displacement -  -  -  -  - (1) \\  \\  \bold{As \: we \: know \: that} \\  \tt:  \implies Force = Mass \times Acceleration -  -  -  -  - (2) \\  \\  \bold{As \: we \: know \: that} \\  \tt:  \implies  {v}^{2}  =  {u}^{2}  + 2as \\  \\ \tt:  \implies  {v}^{2}  =  {0}^{2}  + 2as \\  \\ \tt:  \implies   \frac{ {v}^{2} }{2s}  = a \\  \\ \tt:  \implies  a=  \frac{ {v}^{2} }{2x}  -  -  -  -  - (3) \\  \\  \text{Putting \: value \: of \: (2) \: and \: (3) \: in \: (1)} \\  \\  \tt:  \implies Work \: Done = m \times  \frac{ {v}^{2} }{2x}  \times x \\  \\ \tt:  \implies Work \: Done =  \frac{1}{2} m {v}^{2}  \\  \\ \tt \circ \: Work \: Done = Kinetic \: Energy \\   \\  \green{\tt:  \implies Kinetic \: Energy =  \frac{1}{2} m {v}^{2} } \\  \\       \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \huge{\green{\text{Derived  }}}

Answered by amansharma264
14

 \large \bold \red{ \underline{ \underline{derivation \: of \: k.e =  \frac{1}{2}mv {}^{2}  }}} \\  \large \bold \green{ \underline{ \underline{explanation}}} \\  \large \bold{considerd \: the \: body \: is \: moving \: of \: \: mass \: m \:  \:  moving \: with \: velocity = v \: ms} \\  \\  \large \bold \blue{w =f.s} \\  \large \bold \blue{f = ma} \\ \large \bold \blue{w = m.a.s.......(1)} \\  \large \bold \orange{ \underline{ \underline{by \: third \: equation \: of \: motion}}} \\ \large \bold \green{v {}^{2} =  {u}^{2} + 2as  } \\ \large \bold{here \: u = 0 \:  \: since \: the \: body \: is \: initially \: rest} \\ \large \bold \green{v {}^{2} = 2as } \\ \large \bold \green{as =  \frac{1}{2} {v}^{2}  } \\ \large \bold{substitute \: above \: value \: in \: equation \: (1)} \\ \large \bold \green{w =  \frac{1}{2}m {v}^{2}  } \\ \large \bold \red{ \underline {\underline{k.e =  \frac{1}{2}m {v}^{2} = proved  }}}

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