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Answer 1

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From E= hv or hc/ λ, we have λ = 242nm or 242 x 10-9m

From E= hv or hc/ λ, we have λ = 242nm or 242 x 10-9mC = 3 x 108 m/s

From E= hv or hc/ λ, we have λ = 242nm or 242 x 10-9mC = 3 x 108 m/sh = 6.62 x 10-34 Js

From E= hv or hc/ λ, we have λ = 242nm or 242 x 10-9mC = 3 x 108 m/sh = 6.62 x 10-34 JsNow putting these values in the equation we get

From E= hv or hc/ λ, we have λ = 242nm or 242 x 10-9mC = 3 x 108 m/sh = 6.62 x 10-34 JsNow putting these values in the equation we getE= (6.62 x 10-34 Js x 3 x 108 m/s) / (242 x 10-9m)

From E= hv or hc/ λ, we have λ = 242nm or 242 x 10-9mC = 3 x 108 m/sh = 6.62 x 10-34 JsNow putting these values in the equation we getE= (6.62 x 10-34 Js x 3 x 108 m/s) / (242 x 10-9m)= 0.0821 x 10-17 J/atom

From E= hv or hc/ λ, we have λ = 242nm or 242 x 10-9mC = 3 x 108 m/sh = 6.62 x 10-34 JsNow putting these values in the equation we getE= (6.62 x 10-34 Js x 3 x 108 m/s) / (242 x 10-9m)= 0.0821 x 10-17 J/atom

Answer 2

Answer:

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