solve this don't spam........
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Step-by-step explanation:
64^2x = (2^6)^2x=2^12x
16^x =(2^4)^x=2^4x
128^x=(2^7)^x =2^7x
4^2x=(2^2)^2x=2^4x
64^2x÷16^x = 2^12x ÷ 2^4x =2^(12x-4x)=2^8x
128^x × 4^2x = 2^7x × 2^4x = 2^(7x+4x)=2^11x
64^2x÷16^x 2^8x
_________ = ____
128^x × 4^2x 2^11x
=2^(8x-11x)=2^(-3x)
=(1/2)^3x
=1/8^x
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