Question

Solve this don't spam

Answer 1

Answer:

$\frac{x}{x + 1} = \frac{x + 3}{x + 5} \\ \\ x(x + 5) = (x + 3)(x + 1) \\ \\ {x}^{2} + 5x = {x}^{2} + 4x + 3 \\ \\{ \huge{ \boxed{ \green{ x = 3}}}}$

Answer 2

सवाल –

${\mapsto}$ यदि ∆ ABC में DE || BC हो तो x ki कीमत ज्ञात कीजिए । चित्र लगाव में दिया गया है ( Given in attachment )

दिया गया है –

${\mapsto}$ ( लगाव देखना अनिवार्य है )

∆ ABC में DE || BC है ।

ज्ञात करना है –

${\mapsto}$ x की कीमत ।

हल –

${\mapsto}$ x की कीमत है = 3

समस्त हल –

$\rule{95}{2}$

~

∆ADE = ∆ABC

∆ ABC में DE || BC है

∠ ADE = ∠ ABC

∠ AED = ∠ ACB

$\rule{95}{2}$

~ आनुपातिक निष्क्रियता का उपयोग करके हमें मूल्यों को रखना होगा !

( Now we have to use Proportional theorm and have to put values ! )

${\bold{\sf{\mapsto \dfrac{AD}{AB} = \dfrac{AE}{AC}}}}$ Equation 1

$\rule{95}{2}$

~ सवाल के अनुसार –

${\bullet}$ AD = x

${\bullet}$ AE = x + 3

${\bullet}$ AB = AD + DB ${\longrightarrow}$ x + x + 1 = 2x + 1

${\bullet}$ AC = AE + EC ${\longrightarrow}$ x + 3 + x + 5 ${\longrightarrow}$ ( 2x + 8 )

$\rule{95}{2}$

${\bold{\sf{\mapsto \dfrac{x}{2x+1} = \dfrac{x+3}{2x+8}}}}$

${\mapsto}$ x(2x+8) = 3x+3(2x-1)

${\mapsto}$ 2x²+8x = 2x²+6x+x+3

${\mapsto}$ 8x = 6x + x + 3

${\mapsto}$ 8x = 7x + 3

${\mapsto}$ 8x - 7x = 3

${\mapsto}$ 1x = 3

${\mapsto}$ x = 3

$\rule{95}{2}$

be brainly ❤`~