Question

Solve this easy question buddies .

$\large{QUESTION}$

(5,10) , (-15,15) and (5,15) are the coordinates of vertices A,B,C of triangleABC such that AD : PD = 2:3 . Then ratio of areas of triangle PBC and triangle ABC is
(a) 2:3
(b) 3:4
(c) 3:5
(d) 4:5


may I know kisko kitna aata h xD

balko spam sirf spammed questions pe krte h is lia yha pe answer dene ka sirf ​

Answer 1

★FIND:

$\bold{The\: ratio\: of\:areas \:of\: (triangle) \:PBC \:and\: \\(triangle)\: ABC\:(PBC:ABC)}$ =?

★GIVEN,

$\bold{A(5,10) ,B(-15,15) and C(5,15)}$

$\bold{The\: ratio\: of\: AD:PD=2:3}$

$\bold{AD/PD=2/3}$

$\bold{AD=2 \:and \:PD=3}$

★SOLUTION:

$\bold{Area\:of\: triangle\: ABC=1/2×AD×BC}$

➡️1/2(2)×BC

➡️BC

$\bold{Area \:of\: triangle \:PBC=1/2×PD×BC}$

➡️1/2(3)×BC

➡️3/2(BC)

★NOW,

$= > \frac{area \: of \: triangle \: ABC}{area \: of \: triangl \: PBC} = \frac{BC}{3/2BC} \\ = > \frac{area \: of \: triangle \: ABC}{area \: of \: triangl \: PBC} = \frac{2BC}{3BC} \\ = > \frac{area \: of \: triangle \: ABC}{area \: of \: triangl \: PBC} = 2/3$

Area of ∆ABC:Area of ∆PBC= 2:3

★So,

Option;a) 2:3

Answer 2

$\large{Answer}$
Area of ∆ABC:Area of ∆PBC= 2:3

★So,

Option;a) 2:3