Question

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Ques: A box contains 4 white, 3 black and 5 red balls.3 balls are drawn one by one without replacement.Find the probability of 2 white and 1 black ball.

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Answer 1

Answer:

9/220

Step-by-step explanation:

Total number of balls = 4 + 3 + 5 = 12

Number of ways of selecting 3 balls out of 12 :

= C(12,3)

= 12!/3!(12 - 3)!

= 12!/3!9!

= 2 * 11 * 10

= 220.

Number of ways of selecting 2 white and 1 black ball

=> C(4,2) + C(3,1)

=> 6 + 3

=> 9.

P(getting 2 white and 1 black ball) = 9/220.

Hope it helps!

Answer 2

Answer:

3 White & 4 Red & 5 Black = Total 12 Balls. 2 balls drawn one by one without replacement. = 15/22 Answer.