Question

SOLVE THIS elimination equation BY USING KREMAR METHOD. ​

Answer 1

refer to attachment ...............

Answer 2

Answer:-

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$\tt{3x-4y=10 ---------(1)}$

$\tt{4x+3y=5-----------(2)}$

$\tt{here, a1=3 , b1= -4 , c =10}$ $\tt{and\: a2=4 , b2=3 , c2=5.}$

$d = \: \large\: |a1 \: \: \:b1 | \\ \: \: \: \: \: \: \: \: \: \: \large \: |a2 \: \: \:b2 | \:$

$.°. \: \large \: |3 \: \: \: - 4| \\ \large\: \: \: \: \: \: \: \: |4 \: \: \: \: \: \: \: 3 \: | \: \\ .°. = (3×3) -[(-4)×4] \\ </p><p> = 9+16 \\ </p><p> =\red{25} \:$

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$dx = \: \large \: |c1 \: \: \:b1 | \\ \: \: \: \: \: \: \: \: \: \large \: \: \: \: |c1 \: \: \:b2 | \\ \: \: \: \: \: \: \: \: \: \: \: \: \large \: |10 \: \: \: - 4 | \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \large\: | \: </strong><strong>\</strong><strong>:</strong><strong>\</strong><strong>:</strong><strong>5\: \: \: - 3 | \\ \: = (10 \times 3) - ( - 4 \times 5) \\ = 30 + 20 \\ =</strong><strong>\</strong><strong>red{</strong><strong> 50</strong><strong>}</strong></p><p><strong>\\ dy = \: \large \: |a1 \: \: \:c1 | \\ \: \: \: \: \: \: \: \: \: \: \: \: \large \: |a2 \: \: \:c2 | \: \\ </strong><strong> </strong><strong>\</strong><strong>:</strong><strong> </strong><strong>\</strong><strong>:</strong><strong> \: \large \: |3 \: \: \: \: 10\: | \: \\ \: \large \: \: \: | \: 4 \: \: \: \: \: \: 5 \: \: | \\ = (3 \times 5) - (10 \times 4) \\ = 15 - 40 \\ = </strong><strong>\</strong><strong>red{</strong><strong>- 25 </strong><strong>}</strong><strong>\\ </strong><strong>\</strong><strong>bigstar</strong><strong>\large{according\: to \: kremer \: method</strong><strong>:</strong><strong>-</strong><strong>\: \: } \\ x = \frac{dx}{d} \: \: \: \: \: or \: \: \: y = \frac{dy}{d} \\ x = \frac{\cancel{50}}{\cancel{25}} \: \: \: or \: \: \: \: y = \frac{ \cancel{- 25}}{\cancel{25}} \\\red{ x = 2} \: \: \: \: or \: \: \: \red{y = - 1}$

.°. ANSWER :- (2,-1)

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