Question

Solve this eqaution by factorization method. x^2-2ax+a^2-b^2=0​

Answer 1

Answer:

(x+a+b)×(x+a-b) is ans by using a^2-b^2rule

Answer 2

x^2 - 2ax + a^2 - b^2 = 0

x^2 - 2ax + (a + b)*(a - b) = 0

x^2 - ((a + b) + (a - b))x + (a + b)*(a - b) = 0

x^2 - (a + b)x - (a - b))x + (a + b)*(a - b) = 0

x(x - (a + b)) - (a - b)(x - (a + b)) = 0

(x - (a - b))*(x - (a + b)) = 0

(x - (a - b)) = 0, (x - (a + b)) = 0

x = a - b, x = a + b ——> Answer