Question

solve this eqn to find two roots
$\sqrt{2} {x}^{2} + 7x + 5 \sqrt{2} = 0$
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Answer 1

Answer:

$x = - \sqrt{2} \: and \: \frac{ - 5}{ \sqrt{2} }$

Step-by-step explanation:

$\sqrt{2} {x}^{2} + 7x + 5 \sqrt{2} = 0 \\ \sqrt{2} {x}^{2} + 5x + 2x + 5 \sqrt{2} = 0 \\ \sqrt{2} {x}^{2} + 5x + \sqrt{2} \times \sqrt{2}x + 5 \sqrt{2} = 0 \\ x( \sqrt{2} + 5) + \sqrt{2} ( \sqrt{2} x + 5) = 0 \\ (x + \sqrt{2} )( \sqrt{2} x + 5) = 0 \\ x = - \sqrt{2} \\ x + 5 = 0 \\ \sqrt{2}x = - 5 \\ x = \frac{ - 5}{ \sqrt{2} }$

Answer 2

Step-by-step explanation:

Solution is in the attachment