Math, asked by bharadwaj89, 8 months ago

solve this equation 0.4x÷0.5y=2.3​

Answers

Answered by haripriyasujitha60
0

Step-by-step explanation:

think correct answer

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Answered by amankumaraman11
1

 \huge{ \textbf{ \purple{Correct Question} }}:

Solve the following pair of linear equation --

0.2x + 0.3y = 1.3

0.4x + 0.5y = 2.3

 \huge{ \textbf{ \blue{SOLUTION}}} :

Here,

 \rm{}0.2x + 0.3y = 1.3 \:  \:  \:  \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  ....(1) \\ \rm{} 0.4x + 0.5y = 2.3\:  \:  \:  \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  ....(2)

 \bf{}Multiplying   \:  \: { Eq}^{n}  \:  \: (1) \:  \: by \:  \:  \pink{2},

 \rm 0.4x + 0.6y = 2.6 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: ...(3)

 \small \bf{}Subtracting   \:  \: {Eq}^{n}  \:  \: ( \pink2) \:  \: from \:  \: (\pink3),

 \small \rm{} \cancel{0.4x} + 0.6y - \cancel{0.4x} - 0.5y = 2.6 - 2.3 \\   \rm\to \: 0.1y = 0.3 \\  \rm \to y =   \cancel{\frac{0.3}{0.1} }  \:  \: = 3

 \textbf{Putting value of y in} \:  \bf \: {  {Eq}^{n}  \: (1)},

 \sf{}0.2x + 0.3(3) = 1.3 \\  \to \sf0.2x + 0.9 = 1.3 \\  \to \sf0.2x = 1.3 - 0.9  \\   \to \sf \: 0.2x =  0.4 \\  \to \sf \:  \: x =   \cancel\frac{0.4}{0.2}   \:  \: = 2

Hence,

 \boxed{\boxed{ \huge{ \bf{x =  \red2}}}} \\  \boxed{\boxed{ \huge{ \bf{y =  \red3}}}}

\huge{\boxed{\tt Or, \:  \:  \:  \:\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:   }}

 \rm\frac{0.4x}{0.5y}=2.3\:  \:  \:  \:  \:\:\:  \:  \:\: \\  \\  \rm \frac{0 \cancel.4x}{0\cancel.5y} = 2.3 \\  \\  \rm \frac{4x}{5y}  = 2.3 \\  \\  \rm \frac{x}{y}  =  \frac{2.3}{ \frac{4}{5} }  \\  \\   \rm\frac{x}{y}  =  \frac{2.3 \times 5}{4}  \\  \\  \rm \frac{x}{y}  =  \frac{11.5}{4}  \\   \\  \rm\frac{x}{y}  =  \frac{115}{40}  \\  \\  \rm \frac{x}{y}  =  \frac{23}{8}  \\  \\  \sf \therefore \: x = 23 \:  \:  \:  \:  \:  \: \& \:  \:  \:  \: y = 8

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